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123 100 Given that N = {1, 2, 3, , 100} Then write the subset of N whose element are perfect square numbers

Since the only operation inside the brackets is a single sum, we first add 1 1 to 100 100 to get 101 101 4×3−1 2 + 4 × 3 − 1 Solution Applying BODMAS, we 123 100 5050 Observe that, 1+2+3+4+ +50+51+ +97+98+99+100, =++++ +, =++++ +,

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123 100 Given that N = {1, 2, 3, , 100} Then write the subset of N whose element are perfect square numbers

123 100 Since the only operation inside the brackets is a single sum, we first add 1 1 to 100 100 to get 101 101 4×3−1 2 + 4 × 3 − 1 Solution Applying BODMAS, we

5050 Observe that, 1+2+3+4+ +50+51+ +97+98+99+100, =++++ +, =++++ +,